Dairy Engg HTML Notes by Shakil FE-20

Dairy Engineering – Complete Exam Notes (FE-20)

⚠️ HOW TO USE THESE NOTES This is your ONLY study resource — everything is here. Follow the 2-Day Strategy section first to plan your time. Use the sidebar to jump between topics. All flowcharts, numericals, and exam answers are included.
📅 2-Day Exam Strategy START HERE
🎯 Your Goal: Maximum marks from Butter, Cheese, Condensed Milk, Yoghurt, Platform Tests, Milk Powder Math, Ice Cream numericals.
DAY 1 — Foundation + Core Products
Morning
Milk Basics, Cream Separation (formulas + 1 numerical) — 1.5 hrs
Late Morning
Platform Tests — ALL 7 tests: procedures, interpretation tables — 1.5 hrs
Afternoon
BUTTER — Full process, overrun/yield formulas, 3 numericals — 2 hrs
Evening
CHEESE (Cheddar process, C/F ratio, defects) — 1.5 hrs
Night
Practice drawing: Cream separator, HTST pasteurizer, Butter flowchart, Cheese flowchart — 1 hr
DAY 2 — Products + Numericals + Revision
Morning
CONDENSED MILK (both sweetened + evaporated, sugar ratio numericals) — 2 hrs
Late Morning
YOGHURT (flow diagram, bacteria, defects) + ICE CREAM mix calculation — 1.5 hrs
Afternoon
ALL Numericals — Solve every problem in this file — 2 hrs
Evening
Quick revision: Read all Quick Reference tables — 1 hr
Night
Answer strategy practice + last minute tips — 30 min
💡 Priority Order: Platform Tests > Butter > Condensed Milk > Yoghurt > Cheese > Cream > Pasteurization > Ice Cream > Homogenization
⚡ Quick Reference — All Critical Numbers
🥛 Milk Composition
Water 87.5% | Fat 3.5-4% | Protein 3.2-3.5% | Lactose 4.6-4.8% | SNF 8.5-9%
🔥 Pasteurization Temps
LTLT: 63°C / 30 min | HTST: 72°C / 15 sec | UHT: 135-150°C / 2-5 sec
🧈 Butter PFA Specs
Fat ≥80% | Moisture 16-18% | Curd ≤1.5% | Salt ≤3%
🧀 Cheese PFA Specs
Moisture ≤43% | Fat ≥42% of DM | C/F ratio 0.68-0.70
🥫 Condensed Milk (Sweetened)
Fat ≥9% | TMS ≥31% | Sugar ≥40% | Sugar Ratio 62.5-64.5%
🥫 Evaporated Milk
Fat ≥8% | TMS ≥26% | NO sugar added | Storage ≤7°C
🫙 Yoghurt
Heat: 90-95°C / 30-45 min | Incubation: 42°C / 3-4 hrs | Endpoint: pH 4.5-4.6
🔬 MBRT Quality Scale
≥5h=Very Good | 3-4h=Good | 1-2h=Fair | ≤0.5h=Poor
⚗️ Alcohol Test
68% ethanol | 5ml:5ml (1:1) | Positive=clots=heat-unstable=REJECT
🫙 Cream Separator
Bowl speed: 5000-6000 rpm | Milk fat density: 0.93 | Skim milk density: 1.036
🧈 Churning Temp
7-8°C | Cream fat: 35-40% | Ripening culture: S.lactis + S.diacetilactis + S.cremoris
⚙️ Homogenizer Pressure
Single stage: 1500-2000 psi | Two stage: 2000+500 psi | Temp: 55-65°C
🥛 Milk — Composition, Properties & Types ⭐⭐⭐
Composition of Cow Milk
Component%Exam Note
Water87.5%Most abundant component
Fat3.5–4.0%Legal minimum varies by standard
Protein3.2–3.5%Casein (80%) + Whey proteins (20%)
Lactose4.6–4.8%Reducing sugar; involved in Maillard browning
Ash/Minerals0.7–0.8%Ca, P, K, Na, Mg
SNF (Solids-Not-Fat)8.5–9.0%SNF = Total Solids − Fat
Total Solids12.5–13.0%TS = Fat + SNF
Physico-Chemical Properties
PropertyValue
pH6.6–6.8
Titratable Acidity0.13–0.17% lactic acid
Specific Gravity (at 15°C)1.028–1.032
Freezing Point−0.55°C (Used to detect water adulteration)
Boiling Point100.17°C
Refractive Index1.3440–1.3485
📝 Exam Formula — Fleischmann's Formula for Specific Gravity:
% Fat = (0.8865 × W) + 0.2525 — where W = water content
Richmond's Formula: Total Solids = 1.2F + 2.665 × [100(D−1)/D]
Types of Special Milk
TypeDescription
Toned Milk3% fat, 8.5% SNF (diluted whole milk + skim powder + water)
Double Toned Milk1.5% fat, 9% SNF
Standardized Milk4.5% fat, 8.5% SNF
Reconstituted MilkMilk powder + water reconstituted to liquid
Recombined MilkButterfat + skim milk powder + water
🫙 Cream & Cream Separation ⭐⭐⭐
Cream Classification (FSSR 2011)
TypeFat %Key Note
Low Fat Cream≥25%
Medium Fat Cream≥40%
High Fat Cream≥60%Cream without fat label = High Fat Cream
Key Formulas — Must Memorize!
Formula 1 — SNF in Cream:
%SNF in Cream = [(100 − %Fat_cream) × %SNF_milk] / (100 − %Fat_milk)
Formula 2 — Cream Acidity:
%TA_cream = (%Fat_milk / %Fat_cream) × %TA_milk
Principle of Cream Separation
Based on density difference between milk fat and skim milk:
• Milk fat density at 16°C: 0.93 g/cm³ (lighter)
• Skim milk density at 16°C: 1.036 g/cm³ (heavier)

Stoke's Law (Gravity): V ∝ r² × (ds−df) / η
Stoke's Law (Centrifugal): V ∝ N² (N = bowl speed in rpm) — MOST IMPORTANT
Gravity vs Centrifugal — Comparison
FeatureGravity MethodCentrifugal Method
Speed12–24 hoursMinutes
Fat loss in skim milk≥0.2%≤0.1%
EquipmentShallow pansBowl with stacked discs
HygieneRisk of contaminationEnclosed, hygienic
StatusObsoleteUsed universally ✅
Centrifugal Separator — Key Parts
  • Discs (stacked): Increase separation surface area enormously
  • Top disc (adjustable screw): Controls cream fat % — More cream opening = lower fat % cream
  • Bowl spindle: Connects to drive; rotates at 5000–6000 rpm
  • Inlet (60–70 rpm motor): Slow input speed, geared up to bowl speed
  • Skim milk outlet: Exits from outer zone (heavy phase)
  • Cream outlet: Exits from center (light phase)
⭐ Exam Note — Clumping: Maximum clumping occurs at 7°C. Buffalo milk creams faster than cow milk due to larger fat globules.
🔥 Pasteurization & Sterilization ⭐⭐⭐
Definition: Pasteurization is the process of heating every particle of milk to a specific temperature for a specific time and immediately cooling, to destroy pathogens without significantly altering the composition, flavor, or nutritive value.
MethodFull NameTemperatureTime
LTLTLow Temp Long Time63°C (145°F)30 minutes
HTSTHigh Temp Short Time72°C (161°F)15 seconds
UHTUltra High Temperature135–150°C2–5 seconds
Sterilization (can)In-can sterilization116–118°C15 minutes
HTST Pasteurizer Components (Flow Order)
Balance Tank (Float valve controls flow)
Centrifugal Pump
Regenerator Section (Pre-heat using hot pasteurized milk — saves energy)
Heater Section (Steam or hot water → 72°C)
Holding Tube (15 seconds at 72°C — critical!)
Flow Diversion Valve (FDV) — sends sub-standard milk back to balance tank
Cooling Section (Chilled water → 4°C)
Pasteurized Milk (4°C)
📝 Critical Control Points: Holding tube temperature must NEVER drop below 72°C. The FDV ensures this — if temp drops, milk is diverted back automatically.
⚙️ Homogenization ⭐⭐⭐
Definition: Process of breaking up fat globules in milk into smaller, uniform particles by forcing milk through a small orifice under high pressure, to prevent creaming.
Key Facts
  • Purpose: Reduce fat globule size to <2 microns to prevent creaming
  • Temperature: 55–65°C (optimal — fat in liquid state)
  • Pressure (Single stage): 1500–2000 psi
  • Pressure (Two stage): Stage 1: 2000 psi + Stage 2: 500 psi
  • Effect: Whiter color, better flavor, softer curd, increased digestibility
  • Disadvantage: Increases susceptibility to lipolysis (rancidity) if done cold
Applications
ProductPressure Used
Milk1500–2000 psi
Ice cream mix2000–2500 psi
Cream1000–1500 psi
Evaporated milk2000+500 psi (two-stage)
🧈 Butter Technology ⭐⭐⭐ HIGH PRIORITY
Definition: Butter is the fatty product derived by churning cream or milk or cream and salt, with or without coloring matter.
PFA (1976) Specifications — Must Know!
ComponentStandardExam Tip
Milk Fat≥ 80%Minimum — most important number
Moisture≤ 16% (salted) / ≤ 16% (unsalted)Legal max = 16%
Curd≤ 1.5%
Salt (NaCl)≤ 3%Only for salted butter
Classification of Butter
TypeDescription
Sweet/Fresh Cream ButterFrom pasteurized, unripened cream — mild flavor
Ripened/Cultured Cream ButterFrom ripened (fermented) cream — stronger flavor ⭐
Salted ButterSalt added (1–3%) for preservation and flavor
Unsalted/White ButterNo salt — used for cooking
Whey ButterMade from cream recovered from whey
Important Terms — Define These!
CHURNING: The mechanical agitation of cream to convert the fat from an emulsion of fat-in-water (cream) to an emulsion of water-in-fat (butter). Fat globule membranes are disrupted → fat globules aggregate → butter granules form.
RIPENING: Process of holding pasteurized cream at low temperature after inoculation with starter culture (S. lactis, S. diacetilactis, S. cremoris). Produces: lactic acid (↑flavor), diacetyl (aroma), CO₂. Temp: 8–10°C, Time: 6–15 hours.
WORKING: Process of kneading butter granules to expel buttermilk, produce uniform texture, incorporate salt, and blend added water and color into a homogeneous mass. Produces the final plastic, smooth texture.
Butter Manufacturing — Complete Flow Diagram
Receiving Milk
Pre-heating (38–40°C)
Neutralization (if needed, with Na₂CO₃ — bring acidity to 0.1%)
Separation (Get cream at 35–40% fat)
Standardization (adjust cream fat %)
Pasteurization (90–95°C / 15 sec for cream)
Cooling (7–8°C)
Ripening — Optional (8–10°C, 6–15 hrs with starter culture)
Aging (0–5°C, 2–8 hrs — crystallize fat)
Churning (7–8°C — cream → butter + buttermilk)
Washing (cold water removes buttermilk traces)
Salting + Working (knead, expel water, add salt)
Cooling (10–15°C before packaging)
Packaging + Cold Storage (4°C or below)
Factors Influencing Churnability ⭐⭐⭐
FactorOptimumEffect
Fat % in cream35–40%Too low = slow churning; too high = sticky butter
Churning temperature7–8°CToo high = soft butter; too low = hard to churn
Acidity of cream0.2–0.25% (sweet), 0.35% (ripened)High acidity = faster but weaker butter
PasteurizationRequiredEnsures safety; affects flavor
Agitation speedModerateToo fast = froth; too slow = no churning
Size of churnHalf fullOverloading reduces efficiency
🔢 Butter Overrun & Yield — Formulas & Problems
Overrun % = [(Butter made (B) − Fat in churn (F)) / Fat in churn (F)] × 100
Yield (Y) = [F × (100 + %Overrun)] / 100
Problem 1: From 800 kg of fat, 1000 kg of butter is produced. Find overrun % and verify with yield formula.
Given: B = 1000 kg, F = 800 kg
%Overrun = [(1000 − 800) / 800] × 100 = (200/800) × 100 = 25%
Verify: Y = [800 × (100+25)] / 100 = [800 × 125] / 100 = 1000 kg ✓
Answer: Overrun = 25%
Problem 2: 500 kg cream (40% fat) yields 220 kg butter. Calculate overrun % and yield per kg fat.
Given: Cream = 500 kg, fat = 40%, Fat in churn = 500×0.40 = 200 kg. Butter = 220 kg
%Overrun = [(220 − 200) / 200] × 100 = (20/200) × 100 = 10%
Yield per kg fat = 220/200 = 1.1 kg butter per kg fat
Answer: Overrun = 10%
Defects of Butter ⭐⭐⭐
DefectCausePrevention
Rancid/LipolyticLipase enzyme activity (fat hydrolysis)Proper pasteurization; avoid agitation of cold milk
Oxidized/Tallowy/CardboardyAuto-oxidation of unsaturated fatty acids; copper contaminationAvoid copper equipment; antioxidants; proper packaging
Cheesy/PutridBacterial proteolysis; poor quality creamProper pasteurization; good quality cream
Sour/AcidExcess lactic acid from over-ripeningControl ripening time and temperature
Flat/Lacking flavorUnder-ripening; sweet cream butterAdequate ripening
Feed taintCows fed strong-smelling feeds (onion, garlic, cabbage)Avoid such feeds before milking
Yeasty/FermentedYeast contaminationProper sanitation
DefectCausePrevention
Soft/Oily bodyHigh churning temp; high proportion of soft fats in diet; improper agingChurn at 7-8°C; proper aging at low temp
Crumbly/BrittleLow churning temp; high proportion of hard fatsProper churning temp; adequate working
Gummy/StickyHigh churning temp; too little washingProper temp; adequate washing
GreasyToo much working; high temp during workingProper working conditions
Mealy/GranularToo little working; inadequate salt mixingAdequate working
Leaky/WeepingPoor working; large water droplets not dispersedProper working; good emulsification
DefectCausePrevention
MottledUneven distribution of salt; uneven mixing of colorProper salting; thorough working
Pale/White colorWinter/indoor-fed cows (low carotene in feed)Add annatto color
Wavy/StreakedChurning too fast or too earlyProper churning speed and temperature
Excessive yellowToo much color added; summer milk with high caroteneStandardize color addition
🧀 Cheese Technology ⭐⭐⭐ HIGH PRIORITY
Definition: Cheese is the fresh or ripened solid or semi-solid product obtained by coagulating milk, cream, skim milk, or their combination, with the aid of rennet or other coagulants, and draining the whey.
PFA (1976) Specifications
TypeMoisture MaxFat (of dry matter) Min
Hard Cheese (e.g., Cheddar)≤43%≥42%
Soft Cheese (e.g., Cottage)≤70%≥10%
Classification of Cheese
BasisTypesExamples
Moisture contentHard, Semi-hard, SoftCheddar | Gouda | Cottage
Type of milkCow, Goat, Buffalo, MixedMozzarella (buffalo) | Brie (cow)
Ripening agentBacteria ripened, Mould ripenedCheddar | Roquefort
Method of manufactureRennet coagulated, Acid coagulatedCheddar | Cottage
Scientific Basis of Cheese Making
RIPENING (SOURING): Lactic acid bacteria (starter culture) convert lactose → lactic acid → pH drops → casein destabilized → coagulation when rennet added.

Key pH values: Fresh milk = 6.6–6.8 | After souring = 5.8–6.2 | Isoelectric point of casein = 4.6 | Cheddar curd pressing pH ≈ 5.0–5.2
Cheddar Cheese — Complete Flow Diagram ⭐⭐⭐
Receiving Milk (4.5% fat, 2.7% casein tested)
Pre-heating (35–40°C)
Filtration/Clarification
Standardization (Casein/Fat ratio = 0.68–0.70)
Pasteurization (72°C / 15 sec)
Cooling to Setting Temp (30–32°C)
Starter Addition (1–2% culture)
Ripening (30 min at 30°C)
Rennet Addition (coagulant — calf rennet or microbial)
Coagulation (30–40 min → firm gel)
Cutting Curd (1.5–2 cm cubes)
Cooking/Scalding (38–40°C — expels whey)
Pitching (settle curd at bottom)
Drainage of Whey
Cheddaring ← UNIQUE to Cheddar!
Stack & turn slabs every 15 min at 38°C until pH 5.2–5.4
Milling (cut into small pieces)
Salting (2–3% salt)
Hooping/Pressing (remove remaining whey)
Drying (form rind)
Ripening/Curing (4–10°C, 3–12 months for Cheddar)
Finished Cheddar Cheese
⭐ CHEDDARING — Most Asked Exam Point: Cheddaring is the process UNIQUE to Cheddar cheese where the drained curd slabs are stacked and turned repeatedly at 38°C. This forms characteristic long parallel fibers (stringy texture) and acidifies the curd to pH 5.2–5.4 through continued bacterial action.
Cottage Cheese vs Cheddar — Key Differences
FeatureCheddarCottage Cheese
Milk usedFull fat or standardizedSkim milk
CoagulantRennetAcid (lactic) ± small rennet
CheddaringYes ✅No ❌
PressingYes ✅No ❌
RipeningYes (3–12 months)No ❌ (fresh)
Moisture≤43%~70%
Fat (DM)≥42%Low
Cheese Standardization — C/F Ratio Calculation ⭐⭐⭐
Target Casein/Fat (C/F) ratio = 0.68–0.70
If C/F too low (fat surplus) → Add skim milk
If C/F too high (fat deficit) → Add cream
Problem: Standardize 1000 kg milk (4.5% fat, 2.7% casein) to C/F = 0.70. Available skim milk: 2.8% casein, 0% fat.
Given: Milk fat = 4.5%, Casein = 2.7%, Target C/F = 0.70, SM casein = 2.8%
Fat in 1000 kg = (4.5/100) × 1000 = 45 kg
Required casein = 0.70 × 45 = 31.5 kg
Casein in milk = (2.7/100) × 1000 = 27 kg → Need 4.5 kg more casein
Let SM = kg of skim milk to add
27 + (2.8/100)×SM = 31.5
0.028×SM = 4.5
SM = 4.5/0.028 = 160.7 kg
Answer: Add 160.7 kg skim milk
Cheese Defects
CategoryDefectCause
FlavorBitterExcess rennet; contaminating bacteria; over-ripe
FlavorRancidLipase action (molds, bacteria)
FlavorAcid/SharpToo much starter; over-acidification
BodyPasty/SoftHigh moisture; under-pressed
BodyCrumblyToo low fat; over-acidification
BodyGassy/Open textureColiform contamination (CO₂ production)
ColorPink/RedPigment-producing bacteria (Micrococcus)
FinishCracked rindToo dry curing; poor bandaging
Cheese Scoring System
FactorMax Marks
Flavor45
Body & Texture30
Finish & Appearance15
Color10
Total100
🥫 Condensed Milk Technology ⭐⭐⭐ HIGH PRIORITY
Definition & Classification
Condensed Milk: Products obtained by evaporating part of water from whole milk or fully/partly skimmed milk, with or without addition of sugar.

Key inventor: Gail Borden (USA, 1856) — "Father of milk condensing" — used evaporation under vacuum (in vacuo)
PFA Specifications (1976) — MUST MEMORIZE
TypeFatTMSSugarPreservation
Sweetened Condensed Milk≥9%≥31%≥40%Sugar (osmotic)
Evaporated Milk (Unsweetened)≥8%≥26%NoneHeat sterilization
Sweetened Condensed Skim≤0.5%≥26%≥40%Sugar
Unsweetened Condensed Skim≤0.5%≥20%NoneHeat sterilization
⭐ Critical Difference: Sweetened Condensed Milk is preserved by HIGH SUGAR concentration (osmotic effect). Evaporated Milk is preserved by HEAT STERILIZATION (116–118°C, 15 min).
Sweetened Condensed Milk — Flow Diagram ⭐⭐⭐
Receiving Milk (≤10°C, no antibiotics, no abnormal milk)
Alcohol test + COB test at reception!
Filtration/Clarification (33–40°C)
Standardization (Fat:SNF ratio = 1:2.44)
Forewarming/Pre-heating (115–118°C, No Hold — Flash method)
Purpose: Kill microorganisms, control viscosity, prevent age-thickening
Condensing in Vacuum Pan (2.5:1 ratio, ~55–60°C under vacuum)
Heart of the condensery! Remove water at low temp to prevent damage
Sugar Addition — at END of condensing (sucrose dissolved in water, filtered)
Add at end! NOT before — would increase viscosity and microbial heat resistance
Homogenization (Optional)
Cooling & Crystallization (Controlled — to get lactose crystals <16 microns)
Seeding with fine lactose crystals ensures smooth texture
Packaging (airtight cans) + Storage (≤10°C, humidity <50%)
Evaporated Milk — Flow Diagram
Receiving Milk → Filtration → Standardization
Forewarming (115–118°C, No Hold)
Evaporation (Vacuum, 2.5:1 ratio)
Homogenization (49°C, Two-stage: 2000+500 psi) ← KEY STEP
Prevents fat separation during long storage
Cooling (7°C)
Pilot Sterilization Test (determine stabilizer — Na citrate or Na phosphate)
Packaging (sealed cans)
Sterilization (116–118°C / 15 min, revolving reel)
Cooling (27–32°C) + Shaking (prevent gel)
Storage (≤7°C)
Vacuum Pan — 5 Major Parts ⭐⭐⭐
PartFunction
1. Heating SurfaceSteam coils/jacket/tubes — evaporates water from milk
2. Vapour SpaceAbove milk level — water vapour collects here; has thermometer, vacuum gauge
3. Entrainment SeparatorReclaims milk particles dragged by vapour — prevents milk solid losses
4. CondenserCondenses water vapour using cooling water (~20 kg water per 1 kg vapour)
5. Vacuum Pump / Steam EjectorMaintains partial vacuum so water boils at low temperature (~55°C)
🔢 Sugar Ratio Calculation ⭐⭐⭐
Formula I: %SR = [% sugar / (100 − %TMS)] × 100
Formula II: %SR = [% sugar / (% sugar + % water)] × 100
Optimum Sugar Ratio = 62.5 – 64.5%
Problem 1: Condensed milk contains 31% TMS and 43.1% added sugar. Calculate Sugar Ratio.
%SR = [43.1 / (100 − 31)] × 100
%SR = [43.1 / 69] × 100 = 0.6246 × 100
Answer: Sugar Ratio = 62.5% ✓ (within optimum range)
Problem 2: Find % sugar needed in condensed milk if TMS = 28% and target SR = 64%.
% sugar = [(100 − %TMS) × SR] / 100
% sugar = [(100 − 28) × 64] / 100 = [72 × 64] / 100 = 4608 / 100
Answer: % sugar = 46.08%
🔢 Standardization Numerical — Condensed Milk
Problem 3: 10,000 kg milk (3.60% fat, 8.9% SNF) needs to give condensed milk with 9.05% fat, 31% TMS. Available cream: 40% fat. Find cream to add.
SNF in cream = [(100−40)×8.9]/(100−3.60) = (60×8.9)/96.4 = 534/96.4 = 5.54%
Check ratios: In milk: SNF/Fat = 8.9/3.60 = 2.47 | In condensed: SNF/Fat = (31−9.05)/9.05 = 21.95/9.05 = 2.43 → 2.47 > 2.43 → fat deficit → add cream
Let C = cream (kg) to add:
Fat balance: 360 + 0.4C (kg fat total)
SNF balance: 890 + 0.0554C (kg SNF total)
Ratio: (890 + 0.0554C) / (360 + 0.4C) = 2.43
890 + 0.0554C = 874.8 + 0.972C → 15.2 = 0.9166C → C = 16.6 kg
Answer: Add 16.6 kg cream
Defects of Condensed & Evaporated Milk
DefectCausePrevention
Sandiness (lactose crystals)Incorrect cooling/crystallizationControlled cooling; seeding with fine crystals
Age-thickeningExcessive forewarming; high storage tempOptimal forewarming; store ≤10°C
Mould buttonsAspergillus repens; oxygen in canVacuum packaging; store ≤10°C
Browning (Maillard)Amino acid + lactose + heat → melanoidinsOptimal heat treatment; store cool
BloatsYeast (Torula) contaminationGood sanitation; hermetic seal
Fat separation (evap.)Inadequate homogenizationTwo-stage homogenization (2000+500 psi)
Cooked flavorHigh sterilization heatUHT + aseptic packaging
Feathering in coffeeExcessively high viscosityControl viscosity
🫙 Yoghurt Technology ⭐⭐⭐ HIGH PRIORITY
Definition: Yoghurt is an acidified, coagulated product obtained from milk (or concentrated/reconstituted milk) by fermentation with specific lactic acid-producing bacteria, resulting in a reduction of pH and coagulation of proteins.
Composition
ComponentAmount
Protein5–7%
Fat0–5% (low fat <3%, non-fat <0.5%)
Carbohydrate7.8%
MSNF (target)12% (natural milk = 8.5% → increase with SMP)
Total Solids9–20%
Bacteria Used ⭐⭐⭐
Primary (must know):
Lactobacillus bulgaricus — produces lactic acid, acetaldehyde (aroma)
Streptococcus thermophilus — produces lactic acid, CO₂
• These two work SYMBIOTICALLY — each helps the other grow

Other strains used:
Lactobacillus acidophilus (probiotic)
Streptococcus diacetylactis (diacetyl flavor)
• Yeasts: Saccharomyces lactis (in kefir)
Types of Yoghurt
TypeKey Feature
Set YoghurtInoculated, packed in cups, then incubated → gel forms in container
Stirred YoghurtFermented in large vat, then stirred to break gel → poured into cups
Fluid/Drinkable YoghurtMore water, low viscosity — pourable
Frozen YoghurtFrozen like ice cream — dessert form
Thermized YoghurtHeat-treated after fermentation — extended shelf life
Set Yoghurt — Manufacturing Flow Diagram ⭐⭐⭐
Receiving Milk
Fat Standardization (target: 0%–3.2%+ depending on type)
Protein Standardization — Add Skim Milk Powder (SMP)
Target: MSNF from 8.5% → 12% | Purpose: Improve firmness, reduce syneresis
Complete Mixing (NO air incorporation!)
Heat Treatment (90–95°C for 30–45 min)
Destroys organisms + denatures whey proteins → better gel strength
Homogenization — Optional (2000+500 psi)
Cooling to Fermentation Temperature (42–45°C)
Inoculation with Culture (2–3% yoghurt starter)
Packing (into 150–250 ml cups/sachets) ← Done BEFORE incubation for Set type
Incubation (42°C for 3–4 hours, undisturbed!)
Lactose → Lactic acid | pH drops 6.6 → 4.5–4.6 | Casein coagulates at pH 4.6
Rapid Cooling to 4–5°C (stops fermentation — prevents over-acidification)
Cold Storage (4°C) → Sale within 21–28 days
📝 Key Difference — Set vs Stirred: In SET yoghurt, cups are filled BEFORE incubation → gel forms in cup. In STIRRED yoghurt, fermentation occurs in a large tank → gel is broken by stirring → then filled into cups. Set = firmer gel. Stirred = smooth, creamy.
SMP Addition Calculation ⭐⭐⭐
SMP required (kg) = M × (Pt − Pm) / (Ps − Pt)
Where: M = milk (kg), Pt = target protein %, Pm = milk protein %, Ps = SMP protein % (~36%)
Problem: Standardize 500 kg milk (3.0% protein) to 5.0% protein using SMP (36% protein).
SMP = M × (Pt − Pm) / (Ps − Pt)
SMP = 500 × (5.0 − 3.0) / (36 − 5.0) = 500 × 2.0 / 31.0 = 1000/31
Answer: SMP = 32.26 kg
Defects of Yoghurt ⭐⭐⭐
DefectCausePrevention
Syneresis (whey off)Low protein; inadequate heat treatment; vibration during incubationIncrease MSNF; proper heat treat; undisturbed incubation
Weak body/gelLow protein, short incubation, too little cultureAdd SMP; adequate incubation; proper culture %
Over-acid tasteOver-fermentation; slow cooling; high incubation tempMonitor pH; rapid cooling to 4°C
Flat/bland flavorPoor culture; under-incubation; inhibitors in milkActive culture; proper time; inhibitor test
Contamination/yeastPoor sanitation; post-contaminationGMP; aseptic packing
Lumpy/grainySMP not fully dissolved; poor mixingComplete dissolution; proper mixing
BSTI Standard for Yoghurt (Bangladesh)
Standard: BDS CAC-A-11(a) 2002
Key requirements on label: Date of manufacture, Date of packaging, Sell-by date, Best-before date, Use-by date (expiration), Ingredients list, Barcode
🍦 Ice Cream — Technology & Numericals ⭐⭐⭐
Ice Cream Mix Composition (Standard)
ComponentTypical %
Fat (milk fat)10–14%
Serum Solids / MSNF9–12%
Sugar (sucrose)13–16%
Stabilizer (gelatin/CMC)0.2–0.5%
Emulsifier (mono/diglycerides)0.1–0.2%
Water~60–65%
🔢 Ice Cream Mix Formulation — Solved Problem ⭐⭐⭐
Problem 1: Formulate 100 kg ice cream mix with: Fat 10%, Serum solids 11%, Sugar 14.5%, Stabilizer 0.3%. Available: Whole milk (3.5% fat, 8.5% SNF), Cream (35% fat, 5.6% SNF), SMP (36% protein = ~96% milk solids). Find amounts of whole milk (X), cream (Y), and SMP (Z).
Set up 3 equations from fat, serum solids, and total mass:
Fat: 0.035X + 0.35Y = 10 kg
SNF/Serum: 0.085X + 0.056Y + 0.96Z = 11 kg
Total: X + Y + Z + 14.5 + 0.3 = 100 → X + Y + Z = 85.2 kg
From fat equation: Ratio Y/X can be determined; solve simultaneously:
Result: X ≈ 67.9 kg, Y ≈ 13.4 kg, Z ≈ 3.9 kg
Answer: Whole milk = 67.9 kg | Cream = 13.4 kg | SMP = 3.9 kg | Sugar = 14.5 kg | Stabilizer = 0.3 kg | Total = 100 kg ✓
🔢 Freezing Point Depression — Ice Cream
Problem 2: Find the temperature at which 50% of water freezes in mix (Fat 12%, Serum solids 11%, Sucrose 16%, Gelatin 0.3%).
Total solids = 12+11+16+0.3 = 39.3% → Water = 60.7%
Water frozen (50%) = 30.35% → Unfrozen water = 30.35%
Solutes in unfrozen water: Sugar+SS = 27% in 30.35% water
Concentration = 27/30.35 × 100 = 88.96 g/100g water
Using ΔTf = Kf × m (Kf = 1.86):
m_sucrose = (16/342)/0.3035 = 0.154 mol/kg
m_SS = (11/180)/0.3035 = 0.201 mol/kg
Total m = 0.355 mol/kg
ΔTf = 1.86 × 0.355 = 0.66°C → Freezing temp = −0.66°C
Answer: Temperature = −0.66°C
Empirical Formula: Tf = −0.0054 × (Sugar+SS)² / (100−Fat) — used as quick approximation in practice.
Ice Cream Processing Overview
  • Mix preparation: Blend ingredients (liquid + dry in correct order), no lumps
  • Pasteurization: 68°C/30 min (LTLT) or 80°C/25 sec (HTST)
  • Homogenization: 2000–2500 psi (breaks fat globules, improves texture)
  • Aging: 4°C for 4–24 hours (crystallize fat, hydrate stabilizers)
  • Freezing + whipping: −6°C continuous freezer; overrun 80–100%
  • Hardening: −30 to −40°C blast freezer → final storage at −20°C
🔬 Platform Tests of Milk ⭐⭐⭐ HIGH PRIORITY
Platform Tests: Rapid evaluation tests carried out at Milk Collection Centers or Milk Reception Docks to make quick accept/reject decisions about incoming raw milk.
Classification of Platform Tests
CategoryTests
Physical1. Organoleptic, 2. Sediment Test
Heat Stability3. COB Test, 4. Alcohol Test
Microbiological5. MBRT, 6. Resazurin (RRT)
Chemical/Biological7. Inhibitor Test
Composition8. Lactometer, 9. Gerber Fat, 10. SNF
1. Organoleptic Test
SenseNormalAbnormal → Cause
SightWhite/creamy, uniformPink (mastitis), Yellow (colostrum), Blue (water addition)
SmellClean, pleasant, slightly sweetSour (acidity), Rancid (lipase), Feed taint (onion/cabbage)
TasteSlightly sweet, cleanBitter (proteolysis), Metallic (Cu contamination)
Advantage: No equipment needed, instant, free. Limitation: Subjective, cannot detect microscopic contamination.
2. Sediment Test
Purpose: Detect visible insoluble matter (dirt, feed, manure particles).
Apparatus: Sediment tester (25 cm filter), white lintine/cotton disc (32 mm diameter), 500 ml sample.
Procedure: Pour 500 ml milk through disc → dry disc → compare with standard discs.
Sediment (mg)GradeAction
0.0ExcellentAccept
0.2GoodAccept
0.5FairCaution
1.0AverageInvestigate
≥2.0Poor/Very PoorReject
3. Clot-On-Boiling (COB) Test ⭐⭐⭐
Purpose: Detect high acidity milk (pH <5.6) or abnormal milk (colostrum, mastitis).
Principle: High acidity destabilizes casein → heat causes precipitation → visible clot.
Procedure: 5 ml milk in test tube → boiling water bath 5 min → examine for clot.
ResultObservationInterpretationAction
PASSNo clot, uniformNormal acidity, heat-stableAccept
FAILClots/flakes visibleHigh acidity OR abnormalReject
4. Alcohol Test ⭐⭐⭐ (Very Important!)
Purpose: Rapid assessment of milk heat-stability and mineral balance — especially important for condensed milk and UHT processing.
Principle: 68% ethanol destabilizes casein when mineral balance is disturbed → positive test = heat-unstable.
Reagent: 68% ethyl alcohol by weight (must be exact — affects sensitivity).
Procedure (Must Know for Exam)
Take 5 ml of well-mixed milk sample in clean test tube
Add equal volume (5 ml) of 68% ethyl alcohol (1:1 ratio)
Mix by gently inverting tube 3–4 times (do NOT shake vigorously)
Examine immediately against good light
Record: NEGATIVE (smooth, no particles) or POSITIVE (curd particles/flakes)
ResultObservationInterpretationAction
NegativeSmooth, uniformGood mineral balance, heat-stableAccept
PositiveCurd particles, flakesDisturbed salt balance, heat-unstableReject
⭐ What Alcohol Test Detects: (1) Disturbed mineral balance (Ca/Mg/phosphate ratio), (2) Developed acidity, (3) Abnormal proteins (colostrum, mastitis milk), (4) Heat instability for UHT/condensing. It is NOT purely an acidity test!
5. Inhibitor Test ⭐⭐⭐
Purpose: Detect antibiotics, drugs, pesticides — prevents inhibition of starter cultures in yoghurt/cheese making.
Principle: Inhibited milk → starter cannot grow → no acid production → compared with control.
Procedure
Label 6 tubes: Tubes 1–3 = suspect milk | Tubes 4–6 = control (inhibitor-free) milk
Add 10 ml respective milk to each tube
Heat all tubes to 90°C for 3–5 min (destroy natural microflora)
Cool to starter temp (30–32°C for mesophilic OR 37–42°C for thermophilic)
Add 1 ml active starter to each tube; mix gently
Incubate at optimum temp for 3 hours; remove one tube/set at 1h, 2h, 3h
Measure titratable acidity or pH; compare suspect vs control
ResultInterpretationAction
Suspect acid = Control acidNo inhibitorsAccept for fermentation
Suspect acid < ControlInhibitors presentReject for fermented products
No acid in suspectStrong inhibition (high antibiotic)Reject completely
6. Methylene Blue Reduction Time (MBRT) ⭐⭐⭐
Principle: Methylene blue (blue, oxidized) + bacterial metabolism → Leuco-methylene blue (colorless, reduced). More bacteria = faster decolorization = shorter reduction time.
Procedure
Add 1 ml methylene blue solution to clean test tube
Add 10 ml well-mixed milk; stopper tube
Mix by gentle inversion (3–4 times)
Place in water bath at 35°C; cover to exclude light
First reading at 30 min; then hourly until decolorized (4/5 color gone)
Record time in whole hours from last inversion to endpoint
Time for ReductionQuality GradeBacterial CountAction
≥5 hoursVery Good<50,000/mlAccept
3–4 hoursGood50,000–5,00,000/mlAccept
1–2 hoursFair5,00,000–20,00,000/mlAccept with caution
≤0.5 hoursPoor>20,00,000/mlReject
7. Resazurin Reduction Test (RRT) ⭐⭐⭐
Principle: Two-stage irreversible reduction:
Resazurin (BLUE) → Resorufin (PINK) → Dihydroresorufin (COLORLESS)
Color measured against Lovibond comparator disc (0–6).
Advantage over MBRT: Faster (10 min, 1hr, or 3hr variants), more objective color comparison.
Disc No.ColorGradeAction
6BlueExcellentAccept
5Light blueVery GoodAccept
4PurpleGoodAccept
3Purple-pinkFairInvestigate
2Light pinkPoorReject
1PinkBadReject
0White/ColorlessVery BadReject immediately
Memory Trick: RRT disc 6-4 = ACCEPT (Blue to Purple) | Disc 3 = CAUTION | Disc 2-0 = REJECT (Pink to White)
Comparative Summary — All Platform Tests ⭐⭐⭐
TestTimeDetectsBest ForKey Limitation
Organoleptic1–2 minOff-odors, color, tasteInitial screeningSubjective
Sediment10–15 minVisible dirtCleanlinessMisses dissolved contamination
COB5–7 minHigh acidity, abnormal proteinsHeat stabilityMisses low-acidity contaminated milk
Alcohol2–3 minMineral imbalance, heat instabilityCondensed/UHT milkRequires exact 68% alcohol
Inhibitor3 hoursAntibiotics, drugs, pesticidesFermented productsSlow; doesn't ID specific inhibitor
MBRT30 min–5 hrsTotal bacterial countGeneral qualityAffected by O₂, light, temp
RRT10 min–3 hrsBacterial count, keeping qualityRapid screeningNeeds comparator; cost
Reception Dock Testing Sequence
Step 1: Organoleptic Check (ALL cans)
Step 2: Temperature Check (ALL cans)
Step 3: Alcohol Test (ALL cans) ← Most critical step
Step 4: COB Test (if alcohol positive or suspicious)
Step 5: Sediment Test (random)
Step 6: MBRT/RRT (random sampling)
Step 7: Inhibitor Test (if for fermentation)
Step 8: Composition Tests (Fat, SNF, Acidity — for payment)
🔢 Complete Numerical Problems — All Topics SOLVE ALL
N1. SNF in Cream
Milk has 3.5% fat, 8.7% SNF. Cream produced has 35% fat. Find SNF in cream.
Formula: %SNF_cream = [(100−F_cream) × SNF_milk] / (100−F_milk)
= [(100−35) × 8.7] / (100−3.5) = (65 × 8.7) / 96.5 = 565.5 / 96.5
Answer: SNF in cream = 5.86%
N2. Cream Acidity
Milk has 4.2% fat, 0.17% TA. Cream has 42% fat. Find cream TA.
Formula: Cream TA = (F_milk / F_cream) × TA_milk
= (4.2 / 42) × 0.17 = 0.10 × 0.17 = 0.017%
Answer: Cream acidity = 0.017%
N3. Butter Overrun
800 kg fat gives 1000 kg butter. Find overrun %.
%OR = [(B−F)/F] × 100 = [(1000−800)/800] × 100
= (200/800) × 100 = 25%
Answer: 25% overrun
N4. Butter Yield from % Overrun
If fat in churn = 500 kg and overrun = 18%, find butter yield.
Y = F × (100 + %OR) / 100
= 500 × (100+18) / 100 = 500 × 118 / 100 = 590 kg
Answer: Butter yield = 590 kg
N5. Cheese Standardization (C/F ratio)
1000 kg milk (4.5% fat, 2.7% casein). Add skim milk (2.8% casein) to get C/F = 0.70. Find skim milk needed.
Fat in 1000 kg = 45 kg. Required casein = 0.70 × 45 = 31.5 kg
Current casein = 27 kg. Deficit = 4.5 kg casein
SM = 4.5 / 0.028 = 160.7 kg
Answer: Add 160.7 kg skim milk
N6. Sugar Ratio in Condensed Milk
Condensed milk: 31% TMS, 43.1% sugar. Find sugar ratio.
%SR = [% sugar / (100 − %TMS)] × 100
= [43.1 / (100−31)] × 100 = [43.1 / 69] × 100
Answer: Sugar Ratio = 62.5%
N7. Sugar Addition Calculation
Condensed milk target: TMS = 28%, SR = 64%. Find % sugar needed. Then find sugar to add per 100L milk (TMS of milk = 12.5%).
% sugar = [(100−28) × 64] / 100 = (72 × 64)/100 = 46.08%
Concentration ratio = 28/12.5 = 2.24
Sugar in milk = 46.08 / 2.24 = 20.57% → per 100L: ~20.57 kg sugar
Answer: % sugar = 46.08% in condensed milk; ~20.57 kg per 100L milk
N8. Pearson's Square — Milk Standardization
Mix milk (6% fat) and skim milk (0.5% fat) to get 3% fat standardized milk. Find ratio of whole milk to skim milk.
Using Pearson's Square:
  Whole milk (6%) ──────── (3 − 0.5) = 2.5 parts whole milk
           \    Target: 3%   /
            \              /
  Skim milk (0.5%) ─────── (6 − 3) = 3.0 parts skim milk
Ratio WM:SM = 2.5:3.0 = 5:6
Answer: Mix 2.5 parts whole milk (6%) with 3.0 parts skim milk (0.5%)
N9. Separator Velocity Comparison
Bowl speed increased from 5000 rpm to 6000 rpm. By what factor does separation velocity increase?
From Stoke's Law: V ∝ N² (centrifugal separation)
V₂/V₁ = (N₂/N₁)² = (6000/5000)² = (1.2)² = 1.44
Answer: Velocity increases by 1.44 times (44% increase)
N10. SMP Addition for Yoghurt
Add SMP (36% protein) to 1000 kg milk (3.0% protein) to reach 5.0% protein.
SMP = M × (Pt−Pm) / (Ps−Pt) = 1000 × (5.0−3.0) / (36−5.0)
= 1000 × 2.0 / 31.0 = 2000/31 = 64.5 kg
Answer: Add 64.5 kg SMP
📐 Diagrams Guide — What to Draw & How
⭐ Exam Strategy for Diagrams: ALWAYS draw a labeled diagram for 5-mark and 10-mark process questions. Even a rough but labeled diagram earns 2–3 marks guaranteed!
DiagramMust Draw?Key Labels
Butter manufacturing flowchart✅ PracticeAll 15 steps in order
Cheddar cheese flowchart✅ PracticeInclude "Cheddaring" — unique step
Sweetened condensed milk flowchart✅ PracticeVacuum pan, forewarming, sugar at end
Evaporated milk flowchart✅ PracticeHomogenization, pilot sterilization, sterilization
Set Yoghurt flowchart✅ PracticeHeat treatment conditions, pack THEN incubate
HTST Pasteurizer flow✅ PracticeBalance tank, regenerator, holder, FDV
Cream separator cross-section✅ DescribeDiscs, bowl, top disc, skim/cream outlets
Platform test decision flowchart✅ DescribeAll 8 steps in sequence
Vacuum pan (condensed milk)✅ Describe5 parts: heating surface, vapour space, entrainment sep., condenser, vacuum pump
💡 Exam Tip — Flowchart Format
Always draw flowcharts with boxes and arrows. Write the temperature/time conditions next to each step. Use double boxes for critical steps. Label inputs (raw material) and outputs (finished product) differently.
📝 Previous Year Questions — Model Answers
High-Frequency 2-Mark Questions
QuestionKey Answer Points
What is churning?Mechanical agitation of cream → fat globule membrane rupture → water-in-fat emulsion (butter). Temp: 7–8°C.
Define Overrun%OR = [(Butter made − Fat used) / Fat used] × 100. Non-fat components incorporated into butter.
What is ripening of cream?Holding pasteurized cream with starter culture (S.lactis etc.) at 8–10°C for 6–15 hrs to develop lactic acid and diacetyl flavor.
What is cheddaring?Unique Cheddar process: draining curd slabs are stacked and turned at 38°C until pH 5.2–5.4 → forms parallel fiber structure.
What is Sugar Ratio?%SR = [% sugar / (100−%TMS)] × 100. Optimum: 62.5–64.5%. Controls osmotic preservation of condensed milk.
What is alcohol test?68% ethanol + milk (1:1) → positive (clots) = heat-unstable, disturbed mineral balance → reject. Negative = accept.
MBRT interpretation≥5h = Very Good | 3–4h = Good | 1–2h = Fair | ≤0.5h = Poor. Shorter time = more bacteria.
What is COB test?5 ml milk boiled 5 min → clot = FAIL (reject). Detects high acidity or abnormal milk.
Types of yoghurtSet type, Stirred type, Fluid, Frozen, Thermized.
Forewarming purposeKill microorganisms, prevent uninterrupted boiling in vacuum pan, control age-thickening viscosity.
5-Mark Model Answers
Q: Describe the manufacturing process of butter. [5 marks]

Introduction: Butter is the fat-rich product made from cream by churning.

Process steps (with conditions):
1. Receiving milk → Preheating (38°C) → Separation (cream 35–40% fat)
2. Neutralization if needed (acidity >0.2%) with Na₂CO₃
3. Pasteurization (90°C/15 sec) → Cooling (7°C)
4. Ripening (optional): 8–10°C, 6–15 hrs, starter culture (S.lactis, S.diacetilactis)
5. Aging: 0–5°C, 2–8 hrs (crystallize fat)
6. Churning: 7–8°C (cream → butter granules + buttermilk)
7. Washing: cold water (remove residual buttermilk)
8. Working + Salting: knead to uniform texture, add 1–3% salt
9. Packaging + Storage: 4°C or below

PFA Standards: Fat ≥80%, Moisture ≤16%, Curd ≤1.5%, Salt ≤3%
Q: Explain the Alcohol Test for milk quality assessment. [5 marks]

Purpose: To rapidly assess heat stability of milk, especially for condensed milk and UHT processing. Detects disturbed mineral (Ca/Mg/phosphate) balance, not primarily acidity.

Reagent: 68% ethyl alcohol by weight (critical — must be exact concentration).

Procedure:
1. Take 5 ml milk in test tube
2. Add 5 ml of 68% ethyl alcohol (equal volumes = 1:1 ratio)
3. Invert gently 3–4 times — do NOT shake
4. Examine immediately against good light

Interpretation:
• Negative (no particles): Good mineral balance, heat-stable → ACCEPT
• Positive (curd particles/flakes): Disturbed salts, heat-unstable → REJECT

What it detects: Abnormal milk (colostrum, mastitis), developed acidity, disturbed mineral balance, heat instability.

Precautions: Use exactly 68% alcohol; read immediately; avoid vigorous shaking (false positive); ensure clean glassware.
Q: Describe MBRT test and its interpretation. [5 marks]

Principle: Methylene blue (blue) is reduced by bacterial metabolic activity to leuco-methylene blue (colorless). More bacteria = faster decolorization.

Reagent: Methylene blue tablet dissolved in 200 ml boiled distilled water → stored in amber bottle in dark. Prepare fresh weekly.

Procedure:
1. Add 1 ml methylene blue + 10 ml milk to stopper tube
2. Invert gently → place at 35°C water bath
3. First reading at 30 min, then hourly
4. Endpoint: 4/5 color has disappeared

Interpretation:
≥5 hours = Very Good (<50,000 bacteria/ml) → Accept
3–4 hours = Good (50k–500k/ml) → Accept
1–2 hours = Fair (500k–2M/ml) → Caution
≤0.5 hour = Poor (>2M/ml) → Reject

Factors affecting: Oxygen content, light exposure, temperature, cream/fat content, leucocyte count.
10-Mark Model Answers
Q: Describe the complete manufacturing process of Sweetened Condensed Milk with flowchart. [10 marks]

See the complete flowchart in the Condensed Milk section above. Write all steps with conditions. Key points to emphasize:
1. Reception: ≤10°C, alcohol test mandatory
2. Standardization: Fat:SNF = 1:2.44
3. Forewarming: 115–118°C, No Hold (modern flash method) — most important step, controls viscosity
4. Vacuum Condensing: ~55°C under partial vacuum, 2.5:1 ratio — heart of the process
5. Sugar addition: At END of condensing (not before) — to prevent viscosity increase and microbial heat resistance
6. Sugar Ratio: Must be 62.5–64.5% — preservative effect is osmotic pressure
7. Cooling & crystallization: Control lactose crystal size (<16 microns) to prevent sandiness
8. Packaging: Airtight cans; storage ≤10°C

PFA Standards: Fat ≥9%, TMS ≥31%, Sugar ≥40%
IS Standards: Acidity ≤0.35%, Bacteria ≤500/g, Coliforms = Negative
Q: Classify and explain Platform Tests of milk with procedures and interpretation. [10 marks]

Structure your answer as:
1. Introduction (2 lines): Platform tests = rapid quality assessment at reception dock for accept/reject decisions.
2. Classification table: Physical, Heat Stability, Dye Reduction, Chemical (with test names).
3. Describe 4–5 tests in detail with procedure and interpretation (Organoleptic, Alcohol, COB, MBRT, Inhibitor).
4. Comparative summary table.
5. Reception sequence flowchart.

Use all the content from the Platform Tests section. Focus especially on Alcohol Test and MBRT as these are highest-frequency exam topics.
✍️ Answer Writing Strategy — Maximum Marks
For 2-Mark Questions (2–3 sentences max)
Format
1. Define/state the concept in one clear sentence.
2. Add one key number or mechanism.
3. Never write more than 3 sentences — you waste time.
For 5-Mark Questions
Format
1. One-line definition/introduction (½ mark)
2. Procedure/process in numbered steps with conditions (2–3 marks)
3. Interpretation/results table if applicable (1 mark)
4. Small labeled diagram or flowchart (1 mark)
Target: 1 page, 5–8 minutes writing time.
For 10-Mark Questions
Format
1. Introduction + Definition (1 mark)
2. Classification or types table (1–2 marks)
3. Process steps in detail with temperature/time conditions (4–5 marks)
4. Labeled flowchart/diagram (2 marks)
5. Standards (PFA/BSTI), Defects, or Comparison table (1–2 marks)
Target: 2–2.5 pages, 15–20 minutes writing time.
⭐ Guaranteed Mark Strategies:
• Always include a flowchart for any process question
• Always write temperature/time conditions (e.g., "72°C for 15 sec")
• Use tables whenever comparing two things
• Write PFA/IS standards when available — shows depth
• Underline key terms
• Start each major point on a new line with a number
🚨 Last Minute Tips — Night Before Exam
🧈 Butter Numbers
Fat ≥80% | Churn temp 7-8°C | Overrun: (B-F)/F × 100 | Ripening: 8-10°C / 6-15 hrs
🧀 Cheese Numbers
C/F = 0.68-0.70 | Moisture ≤43% | Scoring: Flavor 45, Body 30, Finish 15, Color 10
🥫 Condensed Milk
Forewarming: 115-118°C No Hold | SR = 62.5-64.5% | Vacuum pan 5 parts | Sandiness = bad crystal size
🫙 Yoghurt
L.bulgaricus + S.thermophilus | Heat: 90-95°C/30-45 min | Incubation: 42°C/3-4 hrs | pH endpoint: 4.5-4.6
🔬 Platform Tests
Alcohol: 68% / 1:1 / positive=reject | MBRT: ≥5h=VG, ≤0.5h=Poor | RRT disc: 6-4=Accept, 3=Caution, 2-0=Reject
🔥 Pasteurization
LTLT: 63°C/30min | HTST: 72°C/15sec | UHT: 135-150°C/2-5sec | Components: Balance tank → pump → regenerator → heater → holder → FDV → cooler
⚠️ Common Mistakes to Avoid:
• Mixing up Sugar Ratio formula with sugar % — SR = sugar/(100−TMS) × 100
• Forgetting cheddaring is UNIQUE to Cheddar (don't write it for cottage cheese)
• Writing wrong alcohol concentration (68%, not 70% or 63%)
• Forgetting that sugar is added at END of condensing (not beginning)
• Confusing MBRT time direction (shorter = worse quality = more bacteria)
• Forgetting homogenization in evaporated milk (49°C, two-stage 2000+500 psi) — critical step!
🕐 Time Management in Exam
Read entire paper first (5 min) → attempt highest-mark questions you know best first → never leave any question blank → for unknown topics, write definition + whatever you know → always draw at least a rough flowchart
✅ Pre-Exam Checklist
🚀
You Got This!
You have everything you need in these notes. Stay calm, write structured answers, draw flowcharts, include conditions. Quality > Quantity. Good luck! 💪

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